Math Open-Ended Question

xpawel18x · Post by **xpawel18x** » 12 Feb 2009 12:19

Guys, I need some help here with this open-ended question from my Algebra 2+Trig class. If anyone wants to go at it, I'd greately appreciate it.

Rectangles A and B are similar. The area of Rectangle A is 30.195 cm squared. The length of Rectangle B is 6.1 cm. Each dimension of Rectangle B is 2/3 of the corresponding dimension of Rectangle A. What is the perimeter of Rectangle B. Explain your answer and show all the work.

Nitrox · Post by **Nitrox** » 12 Feb 2009 12:31

Ok...

So for rect A you have x * y = 30.195
And B you have l = 6.1

And you know the sides of B are 2/3 that of A, therefore you know x (or length of A) is 9.15
And you know x * y = 30.195, and now you know x, so you know y must me 3.3

Then, using the whole 2/3 thing from before, you know w of B is 2/3 of y, or 2/3 of 3.3, or 2.2

So now you know both of the sides of rect B, 6.1cm and 2.2cm
Just add 'em up times 2 and you get the perimeter

16.6cm

I hope I did an ok job explaining it instead of just giving you the answer
If you're confused about any part of it just go ahead and ask!

xpawel18x · Post by **xpawel18x** » 12 Feb 2009 12:34

That was quick! I understand it, Thank You Nitrox.

Nitrox · Post by **Nitrox** » 12 Feb 2009 12:37

hehe, no problem...I like math

It's oddly fun helping like that so feel free to ask all the questions you want! Just specify what kind of answers you want (explantion, answer, both?)